Marketing Management South Asian Perspective Philip Kotler Koshy Jha 14th Editionl [EXCLUSIVE]

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Uveřejněné: 14.10.2022 (více jak 4 měsíci)

Marketing Management South Asian Perspective Philip Kotler Koshy Jha 14th Editionl [EXCLUSIVE]

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Marketing Management South Asian Perspective Philip Kotler Koshy Jha 14th Editionl

Marketing Management: A South Asian Perspective, Philip Kotler, Kevin Lane Keller, Abraham Koshy, Mitileshwar Jha, 14th Edition, Pearson | „THE BOOK USED“. ₹1,295.00
Published: 2017
ISBN: 9785040924971
Number of pages: 528
Overview Marketing Management: A South Asian Perspective by Philip Kotler, Kevin Lane Keller, Abraham Koshy, Mytileshwar Jha, 14th Edition, Pearson | „THE BOOK USED“. ₹1,295.00
This book is a complete description and analysis of marketing and management as if they were presented in South Asia.
South Asia is a very important part of the world with over 600 million people or more than half of the world’s population.

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A:

You cannot do it with sed, sed can only edit the lines where it is. What you can do is to use awk.
You can simply remove the line that contains the keywords (i.e. the process would be:
awk ‚$0 ~ /2014/{close(f)}; /^[0-9:]*$/ {f=$0} $0 ~ /2014/{print f}‘ infile.csv

if you want to replace them by a space, you could do:
awk ‚$0 ~ /2014/{close(f)}; /^[0-9:]*$/ {f=$0} $0 ~ /2014/{print f}‘ infile.csv |
sed’s/
//‘ |
sed’s/(.)/1 /g‘

The way I wrote above is the following:

awk reads the file, the lines are filtered depending on the condition, and a file is redirected to the output if the line matches;
sed removes the new lines because you want to print the original file but they are not needed anymore, the lines are separated by tab;
sed finally adds tabs to the begining and the end of the lines to make the text appear more tidy.

This is all you need to do: the 3 commands.
To demonstrate how awk works, we can use a simple example:
awk ‚$0 ~ /2014/{print $0}‘ infile.txt

$0 variable will hold the whole line (including r
) and the condition will be true if the whole line contains 2014, in this case $0 will contain something like:
/2014/2014.01.14 00:00:00 start
2014.01.14 00:00:00 start

since $0 will contain the whole line, printing just $0 would print the whole line which contains 2014.
And now, when the condition is not true and it does not contain 2014, the line is printed.
For your case, you could do:
awk ‚$0 ~ /2014/{close(f)}; /^[0-9:]*$/ {f=$0} $0 ~ /2014/{print f}‘ infile.csv

to
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